Composing functions (article) | Khan Academy (2024)

Walk through examples, explanations, and practice problems to learn how to find and evaluate composite functions.

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  • Tess Van Horn

    9 years agoPosted 9 years ago. Direct link to Tess Van Horn's post “In practice Q 4, where is...”

    In practice Q 4, where is 4t created? I see where t^2 and 4 come from, but am not sure what puts 4t in

    (70 votes)

    • Mr.Magroo

      9 years agoPosted 9 years ago. Direct link to Mr.Magroo's post “I was stuck on this too, ...”

      Composing functions (article) | Khan Academy (4)

      Composing functions (article) | Khan Academy (5)

      Composing functions (article) | Khan Academy (6)

      I was stuck on this too, but I think the reason is that (t-2)^2 = (t-2)(t-2) . Using the distributive property, you get t^2-4t+4.

      (137 votes)

  • Nigar Kainath

    8 years agoPosted 8 years ago. Direct link to Nigar Kainath's post “(f ∘ g)(x)here, what doe...”

    (f ∘ g)(x)
    here, what does the sign ∘ mean?

    (2 votes)

    • Levi Geadelmann

      8 years agoPosted 8 years ago. Direct link to Levi Geadelmann's post “(f ∘ g)(x) is read "f of ...”

      Composing functions (article) | Khan Academy (10)

      (f ∘ g)(x) is read "f of g of x", so the ∘ translates to "of".
      In this case, if you had functions defined, f(x) and g(x), then to get (f ∘ g)(x) you would substitute g(x) for x inside of f(x). Another way to write it is f(g(x)).

      (18 votes)

  • Rory Avera

    8 years agoPosted 8 years ago. Direct link to Rory Avera's post “How do you know when to u...”

    How do you know when to use the "inside out property" or the composing function?

    (9 votes)

    • Judith Gibson

      8 years agoPosted 8 years ago. Direct link to Judith Gibson's post “It doesn't really matter ...”

      It doesn't really matter --- they will both give the same answer, so it's up to you to choose what works best/easiest for you with the problem you're given at the time!
      (But, of course, you need to be familiar with both techniques.)

      (7 votes)

  • Aditya Mahajan

    5 years agoPosted 5 years ago. Direct link to Aditya Mahajan's post “May someone please explai...”

    May someone please explain the challenge problem to me?

    (4 votes)

    • Dylan Chan

      5 years agoPosted 5 years ago. Direct link to Dylan Chan's post “The challenge problem say...”

      Composing functions (article) | Khan Academy (17)

      The challenge problem says, "The graphs of the equations y=f(x) and y=g(x) are shown in the grid below." So basically the two graphs is a visual representation of what the two different functions would look like if graphed and they're asking us to find (f∘g)(8), which is combining the two functions and inputting 8. From the definition, we know (f∘g)(8)=f(g(8)). So let's work "inside out". If we look at the graph of "g", we see that g(8) is 2 (look at the 8 at the x-axis and if you go up to where it meets the line, the y value would be 2). Because g(8)=2, then when you substitute it back in the equation, f(g(8)) would equal f(2). Then if we look at the graph of "f", we can see that f(2) is -3. (when you look at the 2 in the x-axis, it will correspond to -3 on the y-axis). So by looking at the graph, you can figure out that (f∘g)(8) is approximately -3.
      ~Dylan

      (17 votes)

  • flowermap21

    a year agoPosted a year ago. Direct link to flowermap21's post “In question 4 how do peop...”

    In question 4 how do people get the 4t in tsquered-t4+9?

    (3 votes)

    • Kim Seidel

      a year agoPosted a year ago. Direct link to Kim Seidel's post “It comes from (t-2)^2(t-...”

      Composing functions (article) | Khan Academy (21)

      It comes from (t-2)^2
      (t-2)^2 = (t-2)(t-2) = t^2-2t-2t+4 = t^2-4t+4
      To square binomials, you need to use FOIL or the pattern for creating a perfect square trinomial. You can't square the 2 terms and get the right answer.

      Hope this helps.

      (12 votes)

  • Ceaseless_Thoughts

    a year agoPosted a year ago. Direct link to Ceaseless_Thoughts's post “in the example question "...”

    in the example question "g(x)= x+4, h(x)= x(squared)-2x" how does it get the +8x and -2x in the distribute section ?
    here's the distribute equation =(x(squared)+8x+16−2x−8)

    (5 votes)

    • Kim Seidel

      a year agoPosted a year ago. Direct link to Kim Seidel's post “h(g(x)) = (x+4)^2 - 2(x+4...”

      h(g(x)) = (x+4)^2 - 2(x+4)
      Basically each "x" in h(x) gets replaced with (x+4), which if g(x). Then, you simplify.

      1) FOIL out (x+4)^2:
      h(g(x)) = x^2+4x+4x+16 - 2(x+4) = x^2 + 8x + 16 - 2(x+4)

      2) Distribute -2: h(g(x)) = x^2 + 8x + 16 - 2x - 8

      3) Combine like terms: x^2 + 6x + 8

      Hope this helps.

      (6 votes)

  • ScribofThoth

    a year agoPosted a year ago. Direct link to ScribofThoth's post “I still can't get this. I...”

    I still can't get this. I think my problem is them showing multiple ways to do this instead of focusing on how to combine it into one equation. Either I have to work each function alone then combine them at the end or have more help figuring out how to make one equation.

    (3 votes)

    • ersepsi

      a year agoPosted a year ago. Direct link to ersepsi's post “I don't think their aim i...”

      I don't think their aim is to show you the multiple ways you can evaluate the composite function.

      The first example they basically show what evaluating a composite function really means, it's like you said "work each function alone". In the second example they showed a more faster and efficient way to evaluate the composite function by combining them into one equation.

      If you're still confused about composite functions, I'll explain this way:

      we have a function f(x), this function takes "x" as "input". Now, I'm certain you're used to the variable x being substituted for a number, but in maths, you can pretty much substitute it for anything you like. (Expressions for example)

      Like I can let x = 5, but I can also let x = 2h. Doesn't that mean I can also substitute x for some function? In other words x = g(x).

      Say if g(k) = 4k, then this would become: x = 4k. (Because x = g(k) = 4k)

      Since we let x = g(k) = 4k, then our function f can be written as: f( g(k) ) or f(5k) (We substituted x for g(k) )

      if f(x) = 5x, by substituting x for g(k), this becomes:

      f( g(x) ) = 5g(x) ---> f( 4k ) = 5(4k) = 20k

      This also means that our composite function changes value depending on the value of k.

      Conclusion: g(k) becomes input for function f.

      (8 votes)

  • awesomeness.RM

    8 years agoPosted 8 years ago. Direct link to awesomeness.RM's post “Can someone please simpli...”

    Can someone please simplify all of this for me cause i am so confused!

    (2 votes)

    • Kim Seidel

      8 years agoPosted 8 years ago. Direct link to Kim Seidel's post “Sometimes it's useful to ...”

      Sometimes it's useful to look at a different point of view. Try this site. Then come back and try this video again. http://www.mathsisfun.com/sets/functions-composition.html

      (6 votes)

  • Mercado Oscar

    a year agoPosted a year ago. Direct link to Mercado Oscar's post “Number 3 is hard can u gi...”

    Number 3 is hard can u give better explanations

    (4 votes)

    • jakubjwerner

      a year agoPosted a year ago. Direct link to jakubjwerner's post “The way I understand it a...”

      The way I understand it and I solve it is to always split solution in to steps where each step is solving just single function:

      f(x) = 3x-5
      g(x) = 3-2x
      (g∘f)(3)

      1. We'll solve f(x) as it's on the end. We know that x is 3 so we need to calculate 3*3-5 which is 4

      2. We'll solve g(x). g(x) is wrapping up f(x) so it might look something like g(f(x)) = 3-2(fx) = 3-2(3x-5).

      As we know from step 1 that f(x) = 4 we can just use it as x variable for g. So equation should be g(x) = 3-2*4

      Esentially you can just focus on single function and use your result as x of next function.

      I hope this is helpful and not more confusing.

      (2 votes)

  • Jennifer Laessig

    7 years agoPosted 7 years ago. Direct link to Jennifer Laessig's post “If f(x)=(1/x) and (f/g)(x...”

    If f(x)=(1/x) and (f/g)(x)=((x+4)/(x^2+2x)), what is the function g?

    (4 votes)

    • Kim Seidel

      7 years agoPosted 7 years ago. Direct link to Kim Seidel's post “Based upon the rules for ...”

      Based upon the rules for dividing with fractions: f/g = (1/x) / g = (1/x) * the reciprocal of g

      We need to work in reverse
      1) Factor denominator to undo the multiplication: (x+4)/(x^2+2x) = (x+4)/[x(x+2)]
      We can see there is a factor of X in the denominator. This would have been from multiplying 1/x * the reciprocal of g.
      2) Separate the factor 1/x: (1/x) * (x+4)/(x+2)
      This tells us the reciprocal of g = (x+4)/(x+2)

      3) Flip it to find g: g(x) = (x+2)/(x+4)

      Hope this helps.

      (2 votes)

Composing functions (article) | Khan Academy (2024)
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